日批日出水久久亚洲精品tv,亚洲一区二区三区播放在线,亚洲午夜久久久精品影院

xml面试斚w��问题

jam — Mon, 22 Aug 2005 07:08:00 GMT

、xml有哪些解析技�?区别是什�?

�{?有DOM,SAX,STAX�{?

DOM:处理大型文�g时其性能下降的非常厉実뀂这个问题是由DOM的树(w��i)�l�构所造成的，�q�种�l�构占用的内存较多，而且DOM必须在解析文件之前把整个文档装入内存,适合对XML的随��问SAX:不现于DOM,SAX是事仉��动型的XML解析方式。它��序��d��XML文�g�Q�不需要一�ơ全部装载整个文件。当遇到像文件开��_��文档�l�束�Q�或者标�{�ּ�头与标签�l�束�Ӟ��它会触发一个事�Ӟ��用户通过在其回调事�g中写入处理代码来处理XML文�g�Q�适合对XML的顺序访�?

STAX:Streaming API for XML (StAX)

2、你在项目中用到了xml技术的哪些斚w��?如何实现�?

�{?用到了数据存贮，信息配置两方面。在做数据交换��^台时�Q�将不能数据源的数据�l�装成XML文�g�Q�然后将XML文�g压羃打包加密后通过�|�络传送给接收者，接收解密与解压羃后再同XML文�g中还原相关信息进行处理。在做��Y仉��|�时�Q�利用XML可以很方便的�q�行�Q��Y件的各种配置参数都存贮在XML文�g中�?

3、用jdom解析xml文�g时如何解决中文问�?如何解析?

�{?看如下代�?用编码方式加以解�?

package test;

import java.io.*;

public class DOMTest

{

private String inFile = "c:\people.xml";

private String outFile = "c:\people.xml";

public static void main(String args[])

{

new DOMTest();

}

public DOMTest()

{

try

{

javax.xml.parsers.DocumentBuilder builder =

javax.xml.parsers.DocumentBuilderFactory.newInstance().newDocumentBuilder();

org.w3c.dom.Document doc = builder.newDocument();

org.w3c.dom.Element root = doc.createElement("老师");

org.w3c.dom.Element wang = doc.createElement("�?);

org.w3c.dom.Element liu = doc.createElement("�?);

wang.appendChild(doc.createTextNode("我是王老师"));

root.appendChild(wang);

doc.appendChild(root);

javax.xml.transform.Transformer transformer =

javax.xml.transform.TransformerFactory.newInstance().newTransformer();

transformer.setOutputProperty(javax.xml.transform.OutputKeys.ENCODING, "gb2312");

transformer.setOutputProperty(javax.xml.transform.OutputKeys.INDENT, "yes");

transformer.transform(new javax.xml.transform.dom.DOMSource(doc),

new

javax.xml.transform.stream.StreamResult(outFile));

}

catch (Exception e)

{

System.out.println (e.getMessage());

}

}

}

jam 2005-08-22 15:08 发表评论

java面试题之一

jam — Mon, 22 Aug 2005 06:25:00 GMT

  String subString(String str, int i) {
    String strReturn = "";
    if (str.equals("") || str == null || i == 0) {
      return "";
    }
    for (int j = 1; j <= str.length(); j++) {
      String temp = "";
      temp = str.substring(0, j);
      if (temp.getBytes().length >= i) {
        if (temp.substring(j - 1, j).getBytes().length == 1) {
          strReturn = temp;
        }
        else {
          strReturn = str.substring(0, j - 1);
        }

        break;
      }

    }

    return strReturn;
  }

以上是java面试题：
“编�E�：�~�写一个截取字�W�串的函敎ͼ�输入��Z��个字�W�串和字节数�Q�输��Zؓ按字节数
但是要保证汉字不被截半个�Q�如“我ABC�?�Q�应该截为“我AB”，输入“我ABC汉DEF”，6�Q�应该输��Zؓ“我ABC”而不是“我ABC+汉的半个”�?�?img src ="http://m.tkk7.com/jam/aggbug/10692.html" width = "1" height = "1" />

jam 2005-08-22 14:25 发表评论

jam — Mon, 22 Aug 2005 04:31:00 GMT

1package test;
2
3public class BigInt {
4  public static void main(String arg[]) {
5    new BigInt();
6  }
7
8  public BigInt() {
9    String bigInt1 =
10        "12312311111111111111111111111111111111113132135135465464646546455545";
11    String bigInt2 =
12        "12312311111111111111111111111111111111113132135135465464646546455545";
13    int[] iArr1 = arr(bigInt1);
14    int[] iArr2 = arr(bigInt2);
15    int[] iArr3 = new int[iArr2.length];
16    int iTemp = 0;
17    String flag = "";
18    for (int i = 0; i < iArr1.length; i++) {
19      if (flag.equals("add")) {
20        iTemp = iArr1[i] + iArr2[i] + 1; ;
21      }
22      else {
23        iTemp = iArr1[i] + iArr2[i];
24      }
25      flag = "";
26      if (iTemp > 9999) {
27        iTemp = iTemp - 10000;
28        flag = "add";
29      }
30
31      iArr3[i] = iTemp;
32    }
33    String temp = "";
34    for (int i = 0; i < iArr3.length; i++) {
35
36      if (iArr3[i] < 10) {
37        temp =  "000" + String.valueOf(iArr3[i])+temp;
38
39      }
40      else if (iArr3[i] < 100) {
41        temp = "00" + String.valueOf(iArr3[i])+temp;
42      }
43      else if (iArr3[i] < 1000) {
44        temp = "0" + String.valueOf(iArr3[i])+temp;
45      }
46      else {
47        temp =  String.valueOf(iArr3[i])+temp;
48      }
49
50    }
51    System.out.println(temp);
52  }
53
54  int[] arr(String s) {
55    int j = s.length() / 4;
56
57    int[] ArrOne = new int[j + 1];
58    int iLength;
59    iLength = s.length();
60
61    for (int i = 0; i < j; i++)
62
63    {
64
65      ArrOne[i] = Integer.parseInt(s.substring(iLength - 4 * (i + 1),
66                                               iLength - 4 * i));
67
68    }
69
70    return ArrOne;
71
72  }
73}
74

jam 2005-08-22 12:31 发表评论

jam — Thu, 11 Aug 2005 04:50:00 GMT

在工作中��到ip地址��查的问题�Q�因此自己写了一个checkIPAdress�Ҏ(gu��)��?BR>

1/**
2   * check input is ip or not.
3   * @return a strResult.1 is not ip adress,0 is ipadress
4   */
5
6  private String checkIPAdress(String input) {
7
8    String strResult = "0";
9    //identify the length of the string
10    if (input.length() < 7 || input.length() > 15) {
11      return "1";
12    }
13
14    int startIndex = 0;
15    Vector v = new Vector();
16    int index = 0;
17    startIndex = input.indexOf(".");
18    while (startIndex < input.length() && startIndex != -1) {
19      String temp = input.substring(index, startIndex);
20      v.addElement(temp);
21      index = startIndex + 1;
22      startIndex = input.indexOf(".", startIndex + 1);
23    }
24    v.addElement(input.substring(index));
25    if (v.size() != 4) {
26      return "1";
27    }
28    for (int i = 0; i < v.size(); i++) {
29      try {
30        int iTemp = Integer.parseInt( (String) v.elementAt(i));
31
32        if (iTemp < 0 || iTemp > 254) {
33
34          return "1";
35        }
36
37      }
38      catch (Exception e) {
39        e.printStackTrace();
40        return "1";
41      }
42
43    }
44
45    return strResult;
46
47  }

起始在判断分割ip地址应该使用split�Ҏ(gu��)��。但是因为我�pȝ��中用的是jdk1.2所以采用这个笨�Ҏ(gu��)��Q�如果觉得不爽可以改成split�Q�更方便�?img src ="http://m.tkk7.com/jam/aggbug/9797.html" width = "1" height = "1" />

jam 2005-08-11 12:50 发表评论

EJB介绍

jam — Fri, 05 Aug 2005 01:25:00 GMT

摘要: EJB 1�Q�EJB体系�l�构�Q? 包括客户端、服务器端�? 客户端：包含了调用EJB�l��g特定业务所需的EJB接口(包括本地和远�E�EJB接口)�Q�服务器端处理对象的句柄�? 服务器端�Q�包含了EJB�l��g实现的实例；用来在客��L(f��ng)��... 阅读全文

jam 2005-08-05 09:25 发表评论

随便写一个，java生成随机数字

jam — Thu, 04 Aug 2005 06:43:00 GMT

1    Random random = new Random();
2    String sRand = "";
3    for (int i = 0; i < 4; i++) {
4      String rand = String.valueOf(random.nextInt(10));
5      sRand += rand;
6    }
7    System.out.println("4 random number is "+sRand);

jam 2005-08-04 14:43 发表评论

jam — Tue, 02 Aug 2005 07:48:00 GMT

之前在网上大家给出的�Ҏ(gu��)��都是�Q?BR> byte temp[] = str.getBytes("8859_1");
strResult = new String(temp, "UTF8");
但是�l�过我测试，发现转换不正��。没有正��{换成UTF�?BR>下面�l�出我的实现�Ҏ(gu��)��Q?BR>

1 private OutputStreamWriter outputwriter = null;
2
3 outputwriter = new OutputStreamWriter(out, "UTF-8");
4 outputwriter.write(strValue, 0, strValue.length());

�q�样��ok了，��试�Ҏ(gu��)��Q�将转换后的字符�Ԍ��用ULtra打开�Q�进行字�W��{换UTF到ASCII如果不是��q��O(ji��n)K了！

jam 2005-08-02 15:48 发表评论

jam — Tue, 02 Aug 2005 07:41:00 GMT

用Java写properties文�g�Ӟ��如果直接用setProperties和store�Ҏ(gu��)��往FileOutputStream写，写出来的东西面目全非了。没有正��的格式。因此我使用了这个方法来写，一行一行的诅R��一行一行地写�?

  1/**
  2   * write property.
  3   * @param title parameter defined in properties file
  4   * @param key parameter defined title value
  5   * @return String return value
  6   */
  7  String writeProp(String filePath, String fileName, String title, String key,
  8                   Logger logger) {
  9
10    String strResult = "";
11    String pathAddFile = ""; //write file with path and name
12    String tempFile = "";
13    String strTemp = ""; //use for identify if the modify is success
14    //filePath is null the file in the default path ,else file in the filePath+\+fileName
15    if (filePath.equals("")) {
16      pathAddFile = fileName;
17      tempFile = "temp.properties";
18    }
19    else {
20      pathAddFile = filePath + systemSeparator + fileName;
21      tempFile = filePath + systemSeparator + "temp.properties";
22    }
23    //properties file
24    File aFile = new File(pathAddFile);
25    //temp file
26    File tFile = new File(tempFile);
27    if (!aFile.exists()) {

31      strResult = "error";
32      return strResult;
33    }
34    //set property to properties
35    try {
36      FileReader fr = new FileReader(pathAddFile);
37
38      BufferedReader br = new BufferedReader(fr);
39      try {
40        FileWriter fw = new FileWriter(tempFile);
41        PrintWriter out = new PrintWriter(fw);
42
43        String strLine = br.readLine().trim();
44        while (strLine != null) {
45          //identify if strLine have title,have change key
46          if (strLine.startsWith(title)) {
47            strLine = title + "=" + key;
48            strTemp = "1";
49          }
50          out.write(strLine);
51          out.println();
52          out.flush();
53          //read next line
54          strLine = br.readLine();
55        }
56        fw.close();
57        out.close();
58        //close BufferedReader object
59        br.close();
60         //close file
61        fr.close();
62        //delete properties file
63        if (aFile.exists()) {
64          if (!aFile.delete()) {
68            return "error";
69          }
70        }
71        //rename temp file to properties file
72        if (!tFile.exists()) {
76          return "error";
77        }
78        tFile.renameTo(aFile);
79        if (!strTemp.equals("1")) {
80          //there is no title prop exit so modify failed
85          strResult = "error";
86
87        }
88        return strResult;
89      }
90      catch (IOException ex2) {
91        ex2.printStackTrace();
92        strResult = "error";
93        logger.fatal(
94            "CmnEToyotaExtractProp ----- writeProp ----- failed !");
95        return strResult;
96
97      }
98    }
99    catch (FileNotFoundException ex1) {
100      ex1.printStackTrace();

103      strResult = "error";
104      return strResult;
105    }
106
107  }

该方法实��C��对属性文件参数的修改�?img src ="http://m.tkk7.com/jam/aggbug/9033.html" width = "1" height = "1" />

jam 2005-08-02 15:41 发表评论

jam — Tue, 02 Aug 2005 07:34:00 GMT

但愿�q�次我会坚持下去�Q�写点东西，帮助�q�轻的同志�?img src ="http://m.tkk7.com/jam/aggbug/9032.html" width = "1" height = "1" />

jam 2005-08-02 15:34 发表评论