1,rand(999999) 生成 6 位隨機數
2,puts rand(0xffffff) # 十六進制的
3,puts rand 生成 0-1 之間的任意數
4, def newpass( len )
chars = ("a".."z").to_a + ("A".."Z").to_a + ("0".."9").to_a
newpass = ""
1.upto(len) { |i| newpass << chars[rand(chars.size-1)] }
return newpass
end
puts newpass(15)
ref:
http://snippets.dzone.com/posts/show/491
http://stackoverflow.com/questions/88311/how-best-to-generate-a-random-string-in-ruby
posted on 2009-03-27 19:13
fl1429 閱讀(8290)
評論(5) 編輯 收藏
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