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[收藏]MD5 算法的Java Bean

Posted on 2006-04-02 15:54 ikingqu 閱讀(243) 評(píng)論(0) 編輯收藏所屬分類: JavaSE&JavaEE

? /** **********************************************

?MD5?算法的Java?Bean

? @author :Topcat?Tuppin

?Last?Modified:10,Mar,2001

?************************************************ */

package ?org.waityou.news.util;

import ?java.lang.reflect. * ;

/** *****************************************************************************

?*?md5?類實(shí)現(xiàn)了RSA?Data?Security,?Inc.在提交給IETF?的RFC1321中的MD5?message-digest?算法。

?***************************************************************************** */

public ? class ?MD5? {

???? /*

?????*?下面這些S11-S44實(shí)際上是一個(gè)4*4的矩陣，在原始的C實(shí)現(xiàn)中是用#define?實(shí)現(xiàn)的，?這里把它們實(shí)現(xiàn)成為static

?????*?final是表示了只讀，切能在同一個(gè)進(jìn)程空間內(nèi)的多個(gè)?Instance間共享

????? */

???? static ? final ? int ?S11? = ? 7 ;

???? static ? final ? int ?S12? = ? 12 ;

???? static ? final ? int ?S13? = ? 17 ;

???? static ? final ? int ?S14? = ? 22 ;

???? static ? final ? int ?S21? = ? 5 ;

???? static ? final ? int ?S22? = ? 9 ;

???? static ? final ? int ?S23? = ? 14 ;

???? static ? final ? int ?S24? = ? 20 ;

???? static ? final ? int ?S31? = ? 4 ;

???? static ? final ? int ?S32? = ? 11 ;

???? static ? final ? int ?S33? = ? 16 ;

???? static ? final ? int ?S34? = ? 23 ;

???? static ? final ? int ?S41? = ? 6 ;

???? static ? final ? int ?S42? = ? 10 ;

???? static ? final ? int ?S43? = ? 15 ;

???? static ? final ? int ?S44? = ? 21 ;

???? static ? final ? byte []?PADDING? = ? {? - 128 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,

???????????? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,

???????????? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ,? 0 ?} ;

???? /*

?????*?下面的三個(gè)成員是MD5計(jì)算過程中用到的3個(gè)核心數(shù)據(jù)，在原始的C實(shí)現(xiàn)中?被定義到MD5_CTX結(jié)構(gòu)中

?????*??

????? */

???? private ? long []?state? = ? new ? long [ 4 ];? // ?state?(ABCD)

???? private ? long []?count? = ? new ? long [ 2 ];? // ?number?of?bits,?modulo?2^64?(lsb

???? // ?first)

???? private ? byte []?buffer? = ? new ? byte [ 64 ];? // ?input?buffer

???? /*

?????*?digestHexStr是MD5的唯一一個(gè)公共成員，是最新一次計(jì)算結(jié)果的?16進(jìn)制ASCII表示.

????? */

???? public ?String?digestHexStr;

???? /*

?????*?digest,是最新一次計(jì)算結(jié)果的2進(jìn)制內(nèi)部表示，表示128bit的MD5值.

????? */

???? private ? byte []?digest? = ? new ? byte [ 16 ];

???? /*

?????*?getMD5ofStr是類MD5最主要的公共方法，入口參數(shù)是你想要進(jìn)行MD5變換的字符串

?????*?返回的是變換完的結(jié)果，這個(gè)結(jié)果是從公共成員digestHexStr取得的．

????? */

???? public ?String?getMD5ofStr(String?inbuf)? {

????????md5Init();

????????md5Update(inbuf.getBytes(),?inbuf.length());

????????md5Final();

????????digestHexStr? = ? "" ;

???????? for ?( int ?i? = ? 0 ;?i? < ? 16 ;?i ++ )? {

????????????digestHexStr? += ?byteHEX(digest[i]);

????????}

???????? return ?digestHexStr;

????}

???? // ?這是MD5這個(gè)類的標(biāo)準(zhǔn)構(gòu)造函數(shù)，JavaBean要求有一個(gè)public的并且沒有參數(shù)的構(gòu)造函數(shù)

???? public ?MD5()? {

????????md5Init();

???????? return ;

????}

???? /* ?md5Init是一個(gè)初始化函數(shù)，初始化核心變量，裝入標(biāo)準(zhǔn)的幻數(shù)? */

???? private ? void ?md5Init()? {

????????count[ 0 ]? = ? 0L ;

????????count[ 1 ]? = ? 0L ;

???????? // /*?Load?magic?initialization?constants.

????????state[ 0 ]? = ? 0x67452301L ;

????????state[ 1 ]? = ? 0xefcdab89L ;

????????state[ 2 ]? = ? 0x98badcfeL ;

????????state[ 3 ]? = ? 0x10325476L ;

???????? return ;

????}

???? /*

?????*?F,?G,?H?,I?是4個(gè)基本的MD5函數(shù)，在原始的MD5的C實(shí)現(xiàn)中，由于它們是

?????*?簡單的位運(yùn)算，可能出于效率的考慮把它們實(shí)現(xiàn)成了宏，在java中，我們把它們?實(shí)現(xiàn)成了private方法，名字保持了原來C中的。

????? */

???? private ? long ?F( long ?x,? long ?y,? long ?z)? {

???????? return ?(x? & ?y)? | ?(( ~ x)? & ?z);

????}

???? private ? long ?G( long ?x,? long ?y,? long ?z)? {

???????? return ?(x? & ?z)? | ?(y? & ?( ~ z));

????}

???? private ? long ?H( long ?x,? long ?y,? long ?z)? {

???????? return ?x? ^ ?y? ^ ?z;

????}

???? private ? long ?I( long ?x,? long ?y,? long ?z)? {

???????? return ?y? ^ ?(x? | ?( ~ z));

????}

???? /*

?????*?FF,GG,HH和II將調(diào)用F,G,H,I進(jìn)行近一步變換?FF,?GG,?HH,?and?II?transformations?for

?????*?rounds?1,?2,?3,?and?4.?Rotation?is?separate?from?addition?to?prevent

?????*?recomputation.

????? */

???? private ? long ?FF( long ?a,? long ?b,? long ?c,? long ?d,? long ?x,? long ?s,? long ?ac)? {

????????a? += ?F(b,?c,?d)? + ?x? + ?ac;

????????a? = ?(( int )?a? << ?s)? | ?(( int )?a? >>> ?( 32 ? - ?s));

????????a? += ?b;

???????? return ?a;

????}

???? private ? long ?GG( long ?a,? long ?b,? long ?c,? long ?d,? long ?x,? long ?s,? long ?ac)? {

????????a? += ?G(b,?c,?d)? + ?x? + ?ac;

????????a? = ?(( int )?a? << ?s)? | ?(( int )?a? >>> ?( 32 ? - ?s));

????????a? += ?b;

???????? return ?a;

????}

???? private ? long ?HH( long ?a,? long ?b,? long ?c,? long ?d,? long ?x,? long ?s,? long ?ac)? {

????????a? += ?H(b,?c,?d)? + ?x? + ?ac;

????????a? = ?(( int )?a? << ?s)? | ?(( int )?a? >>> ?( 32 ? - ?s));

????????a? += ?b;

???????? return ?a;

????}

???? private ? long ?II( long ?a,? long ?b,? long ?c,? long ?d,? long ?x,? long ?s,? long ?ac)? {

????????a? += ?I(b,?c,?d)? + ?x? + ?ac;

????????a? = ?(( int )?a? << ?s)? | ?(( int )?a? >>> ?( 32 ? - ?s));

????????a? += ?b;

???????? return ?a;

????}

???? /*

?????*?md5Update是MD5的主計(jì)算過程，inbuf是要變換的字節(jié)串，inputlen是長度，這個(gè)

?????*?函數(shù)由getMD5ofStr調(diào)用，調(diào)用之前需要調(diào)用md5init，因此把它設(shè)計(jì)成private的

????? */

???? private ? void ?md5Update( byte []?inbuf,? int ?inputLen)? {

???????? int ?i,?index,?partLen;

???????? byte []?block? = ? new ? byte [ 64 ];

????????index? = ?( int )?(count[ 0 ]? >>> ? 3 )? & ? 0x3F ;

???????? // ?/*?Update?number?of?bits?*/

???????? if ?((count[ 0 ]? += ?(inputLen? << ? 3 ))? < ?(inputLen? << ? 3 ))

????????????count[ 1 ] ++ ;

????????count[ 1 ]? += ?(inputLen? >>> ? 29 );

????????partLen? = ? 64 ? - ?index;

???????? // ?Transform?as?many?times?as?possible.

???????? if ?(inputLen? >= ?partLen)? {

????????????md5Memcpy(buffer,?inbuf,?index,? 0 ,?partLen);

????????????md5Transform(buffer);

???????????? for ?(i? = ?partLen;?i? + ? 63 ? < ?inputLen;?i? += ? 64 )? {

????????????????md5Memcpy(block,?inbuf,? 0 ,?i,? 64 );

????????????????md5Transform(block);

????????????}

????????????index? = ? 0 ;

????????} ? else

????????????i? = ? 0 ;

???????? // /*?Buffer?remaining?input?*/

????????md5Memcpy(buffer,?inbuf,?index,?i,?inputLen? - ?i);

????}

???? /*

?????*?md5Final整理和填寫輸出結(jié)果

????? */

???? private ? void ?md5Final()? {

???????? byte []?bits? = ? new ? byte [ 8 ];

???????? int ?index,?padLen;

???????? // /*?Save?number?of?bits?*/

????????Encode(bits,?count,? 8 );

???????? // /*?Pad?out?to?56?mod?64.

????????index? = ?( int )?(count[ 0 ]? >>> ? 3 )? & ? 0x3f ;

????????padLen? = ?(index? < ? 56 )? ? ?( 56 ? - ?index)?:?( 120 ? - ?index);

????????md5Update(PADDING,?padLen);

???????? // /*?Append?length?(before?padding)?*/

????????md5Update(bits,? 8 );

???????? // /*?Store?state?in?digest?*/

????????Encode(digest,?state,? 16 );

????}

???? /*

?????*?md5Memcpy是一個(gè)內(nèi)部使用的byte數(shù)組的塊拷貝函數(shù)，從input的inpos開始把len長度的

?????*?字節(jié)拷貝到output的outpos位置開始

????? */

???? private ? void ?md5Memcpy( byte []?output,? byte []?input,? int ?outpos,? int ?inpos,

???????????? int ?len)? {

???????? int ?i;

???????? for ?(i? = ? 0 ;?i? < ?len;?i ++ )

????????????output[outpos? + ?i]? = ?input[inpos? + ?i];

????}

???? /*

?????*?md5Transform是MD5核心變換程序，有md5Update調(diào)用，block是分塊的原始字節(jié)

????? */

???? private ? void ?md5Transform( byte ?block[])? {

???????? long ?a? = ?state[ 0 ],?b? = ?state[ 1 ],?c? = ?state[ 2 ],?d? = ?state[ 3 ];

???????? long []?x? = ? new ? long [ 16 ];

????????Decode(x,?block,? 64 );

???????? /* ?Round?1? */

????????a? = ?FF(a,?b,?c,?d,?x[ 0 ],?S11,? 0xd76aa478L );? /* ?1? */

????????d? = ?FF(d,?a,?b,?c,?x[ 1 ],?S12,? 0xe8c7b756L );? /* ?2? */

????????c? = ?FF(c,?d,?a,?b,?x[ 2 ],?S13,? 0x242070dbL );? /* ?3? */

????????b? = ?FF(b,?c,?d,?a,?x[ 3 ],?S14,? 0xc1bdceeeL );? /* ?4? */

????????a? = ?FF(a,?b,?c,?d,?x[ 4 ],?S11,? 0xf57c0fafL );? /* ?5? */

????????d? = ?FF(d,?a,?b,?c,?x[ 5 ],?S12,? 0x4787c62aL );? /* ?6? */

????????c? = ?FF(c,?d,?a,?b,?x[ 6 ],?S13,? 0xa8304613L );? /* ?7? */

????????b? = ?FF(b,?c,?d,?a,?x[ 7 ],?S14,? 0xfd469501L );? /* ?8? */

????????a? = ?FF(a,?b,?c,?d,?x[ 8 ],?S11,? 0x698098d8L );? /* ?9? */

????????d? = ?FF(d,?a,?b,?c,?x[ 9 ],?S12,? 0x8b44f7afL );? /* ?10? */

????????c? = ?FF(c,?d,?a,?b,?x[ 10 ],?S13,? 0xffff5bb1L );? /* ?11? */

????????b? = ?FF(b,?c,?d,?a,?x[ 11 ],?S14,? 0x895cd7beL );? /* ?12? */

????????a? = ?FF(a,?b,?c,?d,?x[ 12 ],?S11,? 0x6b901122L );? /* ?13? */

????????d? = ?FF(d,?a,?b,?c,?x[ 13 ],?S12,? 0xfd987193L );? /* ?14? */

????????c? = ?FF(c,?d,?a,?b,?x[ 14 ],?S13,? 0xa679438eL );? /* ?15? */

????????b? = ?FF(b,?c,?d,?a,?x[ 15 ],?S14,? 0x49b40821L );? /* ?16? */

???????? /* ?Round?2? */

????????a? = ?GG(a,?b,?c,?d,?x[ 1 ],?S21,? 0xf61e2562L );? /* ?17? */

????????d? = ?GG(d,?a,?b,?c,?x[ 6 ],?S22,? 0xc040b340L );? /* ?18? */

????????c? = ?GG(c,?d,?a,?b,?x[ 11 ],?S23,? 0x265e5a51L );? /* ?19? */

????????b? = ?GG(b,?c,?d,?a,?x[ 0 ],?S24,? 0xe9b6c7aaL );? /* ?20? */

????????a? = ?GG(a,?b,?c,?d,?x[ 5 ],?S21,? 0xd62f105dL );? /* ?21? */

????????d? = ?GG(d,?a,?b,?c,?x[ 10 ],?S22,? 0x2441453L );? /* ?22? */

????????c? = ?GG(c,?d,?a,?b,?x[ 15 ],?S23,? 0xd8a1e681L );? /* ?23? */

????????b? = ?GG(b,?c,?d,?a,?x[ 4 ],?S24,? 0xe7d3fbc8L );? /* ?24? */

????????a? = ?GG(a,?b,?c,?d,?x[ 9 ],?S21,? 0x21e1cde6L );? /* ?25? */

????????d? = ?GG(d,?a,?b,?c,?x[ 14 ],?S22,? 0xc33707d6L );? /* ?26? */

????????c? = ?GG(c,?d,?a,?b,?x[ 3 ],?S23,? 0xf4d50d87L );? /* ?27? */

????????b? = ?GG(b,?c,?d,?a,?x[ 8 ],?S24,? 0x455a14edL );? /* ?28? */

????????a? = ?GG(a,?b,?c,?d,?x[ 13 ],?S21,? 0xa9e3e905L );? /* ?29? */

????????d? = ?GG(d,?a,?b,?c,?x[ 2 ],?S22,? 0xfcefa3f8L );? /* ?30? */

????????c? = ?GG(c,?d,?a,?b,?x[ 7 ],?S23,? 0x676f02d9L );? /* ?31? */

????????b? = ?GG(b,?c,?d,?a,?x[ 12 ],?S24,? 0x8d2a4c8aL );? /* ?32? */

???????? /* ?Round?3? */

????????a? = ?HH(a,?b,?c,?d,?x[ 5 ],?S31,? 0xfffa3942L );? /* ?33? */

????????d? = ?HH(d,?a,?b,?c,?x[ 8 ],?S32,? 0x8771f681L );? /* ?34? */

????????c? = ?HH(c,?d,?a,?b,?x[ 11 ],?S33,? 0x6d9d6122L );? /* ?35? */

????????b? = ?HH(b,?c,?d,?a,?x[ 14 ],?S34,? 0xfde5380cL );? /* ?36? */

????????a? = ?HH(a,?b,?c,?d,?x[ 1 ],?S31,? 0xa4beea44L );? /* ?37? */

????????d? = ?HH(d,?a,?b,?c,?x[ 4 ],?S32,? 0x4bdecfa9L );? /* ?38? */

????????c? = ?HH(c,?d,?a,?b,?x[ 7 ],?S33,? 0xf6bb4b60L );? /* ?39? */

????????b? = ?HH(b,?c,?d,?a,?x[ 10 ],?S34,? 0xbebfbc70L );? /* ?40? */

????????a? = ?HH(a,?b,?c,?d,?x[ 13 ],?S31,? 0x289b7ec6L );? /* ?41? */

????????d? = ?HH(d,?a,?b,?c,?x[ 0 ],?S32,? 0xeaa127faL );? /* ?42? */

????????c? = ?HH(c,?d,?a,?b,?x[ 3 ],?S33,? 0xd4ef3085L );? /* ?43? */

????????b? = ?HH(b,?c,?d,?a,?x[ 6 ],?S34,? 0x4881d05L );? /* ?44? */

????????a? = ?HH(a,?b,?c,?d,?x[ 9 ],?S31,? 0xd9d4d039L );? /* ?45? */

????????d? = ?HH(d,?a,?b,?c,?x[ 12 ],?S32,? 0xe6db99e5L );? /* ?46? */

????????c? = ?HH(c,?d,?a,?b,?x[ 15 ],?S33,? 0x1fa27cf8L );? /* ?47? */

????????b? = ?HH(b,?c,?d,?a,?x[ 2 ],?S34,? 0xc4ac5665L );? /* ?48? */

???????? /* ?Round?4? */

????????a? = ?II(a,?b,?c,?d,?x[ 0 ],?S41,? 0xf4292244L );? /* ?49? */

????????d? = ?II(d,?a,?b,?c,?x[ 7 ],?S42,? 0x432aff97L );? /* ?50? */

????????c? = ?II(c,?d,?a,?b,?x[ 14 ],?S43,? 0xab9423a7L );? /* ?51? */

????????b? = ?II(b,?c,?d,?a,?x[ 5 ],?S44,? 0xfc93a039L );? /* ?52? */

????????a? = ?II(a,?b,?c,?d,?x[ 12 ],?S41,? 0x655b59c3L );? /* ?53? */

????????d? = ?II(d,?a,?b,?c,?x[ 3 ],?S42,? 0x8f0ccc92L );? /* ?54? */

????????c? = ?II(c,?d,?a,?b,?x[ 10 ],?S43,? 0xffeff47dL );? /* ?55? */

????????b? = ?II(b,?c,?d,?a,?x[ 1 ],?S44,? 0x85845dd1L );? /* ?56? */

????????a? = ?II(a,?b,?c,?d,?x[ 8 ],?S41,? 0x6fa87e4fL );? /* ?57? */

????????d? = ?II(d,?a,?b,?c,?x[ 15 ],?S42,? 0xfe2ce6e0L );? /* ?58? */

????????c? = ?II(c,?d,?a,?b,?x[ 6 ],?S43,? 0xa3014314L );? /* ?59? */

????????b? = ?II(b,?c,?d,?a,?x[ 13 ],?S44,? 0x4e0811a1L );? /* ?60? */

????????a? = ?II(a,?b,?c,?d,?x[ 4 ],?S41,? 0xf7537e82L );? /* ?61? */

????????d? = ?II(d,?a,?b,?c,?x[ 11 ],?S42,? 0xbd3af235L );? /* ?62? */

????????c? = ?II(c,?d,?a,?b,?x[ 2 ],?S43,? 0x2ad7d2bbL );? /* ?63? */

????????b? = ?II(b,?c,?d,?a,?x[ 9 ],?S44,? 0xeb86d391L );? /* ?64? */

????????state[ 0 ]? += ?a;

????????state[ 1 ]? += ?b;

????????state[ 2 ]? += ?c;

????????state[ 3 ]? += ?d;

????}

???? /*

?????*?Encode把long數(shù)組按順序拆成byte數(shù)組，因?yàn)閖ava的long類型是64bit的，?只拆低32bit，以適應(yīng)原始C實(shí)現(xiàn)的用途

????? */

???? private ? void ?Encode( byte []?output,? long []?input,? int ?len)? {

???????? int ?i,?j;

???????? for ?(i? = ? 0 ,?j? = ? 0 ;?j? < ?len;?i ++ ,?j? += ? 4 )? {

????????????output[j]? = ?( byte )?(input[i]? & ? 0xffL );

????????????output[j? + ? 1 ]? = ?( byte )?((input[i]? >>> ? 8 )? & ? 0xffL );

????????????output[j? + ? 2 ]? = ?( byte )?((input[i]? >>> ? 16 )? & ? 0xffL );

????????????output[j? + ? 3 ]? = ?( byte )?((input[i]? >>> ? 24 )? & ? 0xffL );

????????}

????}

???? /*

?????*?Decode把byte數(shù)組按順序合成成long數(shù)組，因?yàn)閖ava的long類型是64bit的，

?????*?只合成低32bit，高32bit清零，以適應(yīng)原始C實(shí)現(xiàn)的用途

????? */

???? private ? void ?Decode( long []?output,? byte []?input,? int ?len)? {

???????? int ?i,?j;

???????? for ?(i? = ? 0 ,?j? = ? 0 ;?j? < ?len;?i ++ ,?j? += ? 4 )

????????????output[i]? = ?b2iu(input[j])? | ?(b2iu(input[j? + ? 1 ])? << ? 8 )

???????????????????? | ?(b2iu(input[j? + ? 2 ])? << ? 16 )? | ?(b2iu(input[j? + ? 3 ])? << ? 24 );

???????? return ;

????}

???? /*

?????*?b2iu是我寫的一個(gè)把byte按照不考慮正負(fù)號(hào)的原則的＂升位＂程序，因?yàn)閖ava沒有unsigned運(yùn)算

????? */

???? public ? static ? long ?b2iu( byte ?b)? {

???????? return ?b? < ? 0 ? ? ?b? & ? 0x7F ? + ? 128 ?:?b;

????}

???? /*

?????*?byteHEX()，用來把一個(gè)byte類型的數(shù)轉(zhuǎn)換成十六進(jìn)制的ASCII表示，

?????*?因?yàn)閖ava中的byte的toString無法實(shí)現(xiàn)這一點(diǎn)，我們又沒有C語言中的?sprintf(outbuf,"%02X",ib)

????? */

???? public ? static ?String?byteHEX( byte ?ib)? {

???????? char []?Digit? = ? {? ' 0 ' ,? ' 1 ' ,? ' 2 ' ,? ' 3 ' ,? ' 4 ' ,? ' 5 ' ,? ' 6 ' ,? ' 7 ' ,? ' 8 ' ,? ' 9 ' ,? ' A ' ,

???????????????? ' B ' ,? ' C ' ,? ' D ' ,? ' E ' ,? ' F ' ?} ;

???????? char []?ob? = ? new ? char [ 2 ];

????????ob[ 0 ]? = ?Digit[(ib? >>> ? 4 )? & ? 0X0F ];

????????ob[ 1 ]? = ?Digit[ib? & ? 0X0F ];

????????String?s? = ? new ?String(ob);

???????? return ?s;

????}

???? public ? static ? void ?main(String?args[])? {

????????MD5?m? = ? new ?MD5();

???????? if ?(Array.getLength(args)? == ? 0 )? {? // 如果沒有參數(shù)，執(zhí)行標(biāo)準(zhǔn)的Test?Suite

????????????System.out.println( " MD5?Test?suite: " );

????????????System.out.println( " MD5(\ " 850817 \ " ): " ? + ?m.getMD5ofStr( " 850817 " ));

????????????System.out.println( " MD5(\ " \ " ): " ? + ?m.getMD5ofStr( "" ));

????????????System.out.println( " MD5(\ " a\ " ): " ? + ?m.getMD5ofStr( " a " ));

????????????System.out.println( " MD5(\ " abc\ " ): " ? + ?m.getMD5ofStr( " abc " ));

????????????System.out.println( " MD5(\ " message?digest\ " ): "

???????????????????? + ?m.getMD5ofStr( " message?digest " ));

????????????System.out.println( " MD5(\ " abcdefghijklmnopqrstuvwxyz\ " ): "

???????????????????? + ?m.getMD5ofStr( " abcdefghijklmnopqrstuvwxyz " ));

????????????System.out

????????????????????.println( " MD5(\ " ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789\ " ): "

???????????????????????????? + ?m

????????????????????????????????????.getMD5ofStr( " ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789 " ));

????????} ? else

????????????System.out

????????????????????.println( " MD5( " ? + ?args[ 0 ]? + ? " )= " ? + ?m.getMD5ofStr(args[ 0 ]));

????}

}

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