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計算某個方法的執(zhí)行時間

1 package assemblyLanguage;
2 import java.math.BigInteger;
3 import java.util.Date;
4 import java.util.Scanner;
5
6
7 public class Add {
8
9     /**
10      * @param args
11      * Write a complete 8086 assembly language program to calculate and display the value of the expression:
12      * "1 + (2+2) + 3 + (4+4) + 5 + (6+6) + 7

+ 9 + (10+10) + 11 +

+ N".
13      *  Notice the fact that the even numbers are added twice.
14      *  N should be input from the keyboard. A LOOP structure is required.
15      *   Use a pseudocode or flowchart to sketch your ideas and plan the overall logic
16      *   before you write the program.
17
18     static int  add(int n)
19     {
20         int result = 0;
21         for(int i = 1; i <= n; i++)
22         {
23             int temp = i;
24             if(temp % 2 == 0)
25                 {
26                 temp *=2;
27                 }
28             result += temp;
29
30         }
31         return result;
32     }
33     */
34     static BigInteger add(BigInteger n) throws Exception
35     {
36         BigInteger result = new BigInteger("0"),
37                     TWO = new BigInteger("2");
38         BigInteger temp = null;
39         for(BigInteger i = BigInteger.ONE; i.compareTo(n) <= 0; i=i.add(BigInteger.ONE))
40         {
41             temp = i;
42             if(temp.remainder(TWO).compareTo(BigInteger.ZERO) == 0)
43                 {
44                 temp=temp.multiply(TWO);
45 //                temp=temp.add(temp);
46                 }
47             result = result.add(temp);
48
49         }
50         return result;
51     }
52     public static void main(String[] args) throws Exception {
53         // TODO 自動生成方法存根
54
55         Scanner reader = new Scanner(System.in);
56         System.out.print("Please input an integer: ");
57         BigInteger a = reader.nextBigInteger();
58         System.out.print("1+(2+2)+3+(4+4)+5+

+N(N=" + a.toString() + ")= ");
59         Date date1 = new Date();
60         System.out.println(add(a).toString());
61         Date date2 = new Date();
62         long totalTime = date2.getTime() - date1.getTime();
63         System.out.println("用時:"+ totalTime+"ms");
64
65     }
66
67 }
68

posted on 2008-12-20 00:32 YXY 閱讀(673) 評論(0) 編輯收藏

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計算某個方法的執(zhí)行時間