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java讀寫刪.text,.xml文件內容

package ?com.paiao.bdpm.flow.base;
?2

import ?java.io.BufferedReader;
?4

import ?java.io.BufferedWriter;
?5

import ?java.io.File;
?6

import ?java.io.FileReader;
?7

import ?java.io.FileWriter;
?8

public ? class ?ReadTextFile? {
10

???? public ?BufferedReader?bufread;
11

???? public ?BufferedWriter?bufwriter;
12

????File?writefile;
13

????String?filepath,?filecontent,?read;
14

????String?readStr? = ? "" ;
15

???? // 從文本文件中讀取內容
16

???? public ?String?readfile(String?path)???
17

???? {
18

???????? try ? {
19

????????????filepath? = ?path;? // 得到文本文件的路徑
20

????????????File?file? = ? new ?File(filepath);
21

????????????FileReader?fileread? = ? new ?FileReader(file);
22

????????????bufread? = ? new ?BufferedReader(fileread);
23

???????????? while ?((read? = ?bufread.readLine())? != ? null )? {
24

????????????????read? = ?read + " \r\n " ;????????????
25

????????????????readStr? = ?readStr? + ?read;
26

????????????}
27

????????} ? catch ?(Exception?d)? {
28

????????????System.out.println(d.getMessage());
29

????????}
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???????? return ?readStr;? // 返回從文本文件中讀取內容
31

????}
32

???? // 向文本文件中寫入內容
34

???? public ? void ?writefile(String?path,?String?content,? boolean ?append)? {
35

???????? try ? {
36

???????????? boolean ?addStr? = ?append;? // 通過這個對象來判斷是否向文本文件中追加內容
37

????????????filepath? = ?path;? // 得到文本文件的路徑
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????????????filecontent? = ?content;? // 需要寫入的內容
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????????????writefile? = ? new ?File(filepath);
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???????????? if ?(writefile.exists()? == ? false )? // 如果文本文件不存在則創建它?
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???????????? {
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????????????????writefile.createNewFile();
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????????????????writefile? = ? new ?File(filepath);? // 重新實例化
44

????????????}
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????????????FileWriter?filewriter? = ? new ?FileWriter(writefile,?addStr);
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???????????? // 刪除原有文件的內容
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????????????java.io.RandomAccessFile?file = ? new ?java.io.RandomAccessFile(path, " rw " );
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????????????file.setLength( 0 );
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???????????? // 寫入新的文件內容
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????????????filewriter.write(filecontent);
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????????????filewriter.close();
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????????????filewriter.flush();
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????????} ? catch ?(Exception?d)? {
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????????????System.out.println(d.getMessage());
55

????????}
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????}
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???? public ? static ? void ?main(String[]?args)? throws ?Exception? {
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????????ReadTextFile?parse? = ? new ?ReadTextFile();
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????????String?filecontent? = ?parse.readfile( " c:/applicationContext.xml " );????????
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????????parse.writefile( " c:/applicationContext.xml " ,filecontent, true );
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????????
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????}
64

}

posted on 2007-08-15 15:10 JJCEA 閱讀(3196) 評論(0) 編輯收藏所屬分類: java文件操作

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