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Posted on 2007-12-06 23:05 蜀山兆孨龘 閱讀(8074) 評(píng)論(4) 編輯 收藏
| C 庫(kù)函數(shù) feof(FILE*) 判斷文件末尾的問(wèn)題 |
A Problem on Using C Library Function feof(FILE*) to Judge The End of A File |
| 我用 C 寫(xiě)了一個(gè)程序讀取 32768 字節(jié)大小的文件，每次讀 16 個(gè)字節(jié)，應(yīng)該是 2048 次讀完。但結(jié)果讀了 2049 次，并且最后兩次的數(shù)據(jù)相同，似乎重復(fù)讀取了最后 16 個(gè)字節(jié)。源代碼如下： |
I wrote a program with C, which read a file of 32768 bytes, 16 bytes each time, and it should finish reading after 2048 times. But the reault was it read 2049 times, and the data of last two times are the same, which seemed the last 16 bytes were read twice. Here is the code: |
- int loop = 0;
- while (!feof(file)) {
- loop++;
- fread(buffer, 16, 1, file);
- ......
- }
- printf("%d\n", loop); // 2049
|
| 我看了一陣，發(fā)現(xiàn)導(dǎo)致這個(gè)錯(cuò)誤的原因是 feof(FILE*) 判斷文件末尾的機(jī)制：文件指針在文件末尾的時(shí)候，除非再讀一次導(dǎo)致發(fā)生 I/O 錯(cuò)誤，feof(FILE*) 依然返回 0。因此用 feof(FILE*) 作為判斷條件的 while 循環(huán)始終會(huì)多讀一次，而最后一次的讀取是失敗的，buffer 也就沒(méi)有改變，看起來(lái)就像是重復(fù)讀了一次。 |
I reviewed it for a whil and found the reason that produced this error is the mechanism feof(FILE*) used to judge the end of a file: When the file pointer is at the end of a file, feof(FILE*) still returns 0 unless reads one more time to course a I/O error. Therefore, a while loop using feof(FILE*) as the judgment condition always reads one more time, and the last time of reading will fail, so buffer stayed unchanged which looked like it repeated reading once. |
| 用下面的代碼就沒(méi)問(wèn)題了： |
Use the code below to solve this problem: |
- int loop = 0;
- while (fread(buffer, 16, 1, file) == 1) {
- loop++;
- ......
- }
- printf("%d\n", loop); // 2048
|
評(píng)論
其實(shí)可以在循環(huán)體內(nèi)加上一句：
if(feof(file))break;
我估計(jì)就行了。
# re: C 庫(kù)函數(shù) feof(FILE*) 判斷文件末尾的問(wèn)題[未登錄](méi) 回復(fù) 更多評(píng)論
2014-10-31 17:52 by
上面結(jié)論是對(duì)的，但下面的代碼也是有問(wèn)題的，
int loop = 0;
while (fread(buffer, 16, 1, file) == 1) {
loop++;
......
}
printf("%d\n", loop); // 2048
應(yīng)該改成：
int loop = 0;
while (fread(buffer, 16, 1, file) ！=1) {
loop++;
......
}
printf("%d\n", loop); // 2048
if(feof(file)==EOF)
....
if(ferror(file))
....
# re: C 庫(kù)函數(shù) feof(FILE*) 判斷文件末尾的問(wèn)題[未登錄](méi) 回復(fù) 更多評(píng)論
2014-10-31 17:59 by
@barry
sorry,
while (fread(buffer, 16, 1, file) ！=1
應(yīng)該還是
while (fread(buffer, 16, 1, file) ==1
只是最后結(jié)束循環(huán)次數(shù)未必一定是2048
因?yàn)榧词沟扔?,也可能是出錯(cuò)的情況之一，這時(shí)候循環(huán)不會(huì)停止。
如果要求出錯(cuò)馬上退出，只能在循環(huán)中判斷。
# re: C 庫(kù)函數(shù) feof(FILE*) 判斷文件末尾的問(wèn)題[未登錄](méi) 回復(fù) 更多評(píng)論
2014-10-31 18:28 by
尤其是塊數(shù)是N,而不是1的情況下，這樣寫(xiě)更有意義
while (fread(buffer, 16, N, file) ==N
最后結(jié)束的時(shí)候，返回的塊數(shù)大多數(shù)情況下會(huì)小于N,這個(gè)時(shí)候，也有可能是因?yàn)槌鲥e(cuò)，沒(méi)有讀完N就出來(lái)了，或者到文件尾，剩下的塊小于N,也跑出來(lái)。
后面要檢測(cè)不同結(jié)果，因?yàn)樽罱K循環(huán)結(jié)束，未必是文件讀完了。
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