exists (sql 返回結果集為真)
not exists (sql 不返回結果集為真)
如下:
表A
ID NAME
1 A1
2 A2
3 A3
表B
ID AID NAME
1 1 B1
2 2 B2
3 2 B3
表A和表B是1對多的關系 A.ID => B.AID
SELECT ID,NAME FROM A WHERE EXIST (SELECT * FROM B WHERE A.ID=B.AID)
執行結果為
1 A1
2 A2
原因可以按照如下分析
SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=1)
---> SELECT * FROM B WHERE B.AID=1有值返回真所以有數據
SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=2)
---> SELECT * FROM B WHERE B.AID=2有值返回真所以有數據
SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE B.AID=3)
---> SELECT * FROM B WHERE B.AID=3無值返回真所以沒有數據
NOT EXISTS 就是反過來
SELECT ID,NAME FROM A WHERE NOT EXIST (SELECT * FROM B WHERE A.ID=B.AID)
執行結果為
3 A3
===========================================================================
EXISTS = IN,意思相同不過語法上有點點區別,好像使用IN效率要差點,應該是不會執行索引的原因
SELECT ID,NAME FROM A WHERE ID IN (SELECT AID FROM B)
NOT EXISTS = NOT IN ,意思相同不過語法上有點點區別
SELECT ID,NAME FROM A WHERE ID NOT IN (SELECT AID FROM B)
posted on 2008-03-19 10:21
湘江夜游神 閱讀(379)
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