如何最快速度刪除？
" <script src=http://3b3.org/c.js> </script> "
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進入SQL查詢分析器
選擇你的數據庫
第一步：先sql表修改所有者為dbo
EXEC sp_MSforeachtable 'exec sp_changeobjectowner ' '? ' ', ' 'dbo ' ' '

第二步：統一刪除字段被掛的js

declare @delStr nvarchar(500)
set @delStr= ' <script src=http://3b3.org/c.js> </script> '

set nocount on

declare @tableName nvarchar(100),@columnName nvarchar(100),@tbID int,@iRow int,@iResult int
declare @sql nvarchar(500)

set @iResult=0
declare cur cursor for
select name,id from sysobjects where xtype= 'U '

open cur
fetch next from cur into @tableName,@tbID

while @@fetch_status=0
begin
declare cur1 cursor for
--xtype in (231,167,239,175,35) 為char,varchar,nchar,nvarchar,text類型
select name from syscolumns where xtype in (231,167,239,175,35) and id=@tbID
open cur1
fetch next from cur1 into @columnName
while @@fetch_status=0
begin
set @sql= 'update [ ' + @tableName + '] set [ '+ @columnName + ']= replace([ '+@columnName+ '], ' ' '+@delStr+ ' ' ', ' ' ' ') where [ '+@columnName+ '] like ' '% '+@delStr+ '% ' ' '
exec sp_executesql @sql
set @iRow=@@rowcount
set @iResult=@iResult+@iRow
if @iRow> 0
begin
print '表： '+@tableName+ ',列: '+@columnName+ '被更新 '+convert(varchar(10),@iRow)+ '條記錄; '
end
fetch next from cur1 into @columnName


end
close cur1
deallocate cur1

fetch next from cur into @tableName,@tbID
end
print '數據庫共有 '+convert(varchar(10),@iResult)+ '條記錄被更新!!! '

close cur
deallocate cur
set nocount off
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徹底杜絕SQL注入

1.不要使用sa用戶連接數據庫
2、新建一個public權限數據庫用戶，并用這個用戶訪問數據庫
3、[角色]去掉角色public對sysobjects與syscolumns對象的select訪問權限
4、[用戶]用戶名稱-> 右鍵－屬性－權限－在sysobjects與syscolumns上面打“×”
5、通過以下代碼檢測（失敗表示權限正確，如能顯示出來則表明權限太高）：
DECLARE @T varchar(255),
@C varchar(255)
DECLARE Table_Cursor CURSOR FOR
Select a.name,b.name from sysobjects a,syscolumns b
where a.id=b.id and a.xtype= 'u ' and (b.xtype=99 or b.xtype=35 or b.xtype=231 or b.xtype=167)
OPEN Table_Cursor
FETCH NEXT FROM Table_Cursor INTO @T,@C
WHILE(@@FETCH_STATUS=0)
BEGIN print @c
FETCH NEXT FROM Table_Cursor INTO @T,@C
END
CLOSE Table_Cursor
DEALLOCATE Table_Cursor