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hibernate關系映射(一對多)

Posted on 2008-08-21 12:00 H2O 閱讀(344) 評論(0) 編輯收藏所屬分類: hibernate

客戶與訂單---一對多

package com.yz.pojos;

import java.util.HashSet;
import java.util.Set;

/** *//**
* Customer generated by MyEclipse Persistence Tools
*/

public class Customer implements java.io.Serializable {

    // Fields

    private Integer cid;

    private String name;

    private String addr;
    //一個客戶可以有多個訂單，一對多關系。但是一個客戶不能有重復的訂單，所以用Set集合，set集合不允許出現重復值
    //set集合反映了一個客戶的所有訂單

    private Set orderses = new HashSet(0);

    // Constructors

    /** *//** default constructor */
    public Customer() {
    }

    /** *//** minimal constructor */
    public Customer(String name) {
        this.name = name;
    }

    /** *//** full constructor */
    public Customer(String name, String addr, Set orderses) {
        this.name = name;
        this.addr = addr;
        this.orderses = orderses;
    }

    // Property accessors

    public Integer getCid() {
        return this.cid;
    }

    public void setCid(Integer cid) {
        this.cid = cid;
    }

    public String getName() {
        return this.name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getAddr() {
        return this.addr;
    }

    public void setAddr(String addr) {
        this.addr = addr;
    }

    public Set getOrderses() {
        return this.orderses;
    }

    public void setOrderses(Set orderses) {
        this.orderses = orderses;
    }

}

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
    <class name="com.yz.pojos.Customer" table="customer" lazy="false" >
        <id name="cid" type="java.lang.Integer">
            <column name="cid" />
            <generator class="native" />
        </id>
        <property name="name" type="java.lang.String">
            <column name="name" length="20" not-null="true" />
        </property>
        <property name="addr" type="java.lang.String">
            <column name="addr" length="50" />
        </property>
        
        <set name="orderses"  lazy="true" cascade="delete" inverse="true">
            <key>
                <column name="cid" not-null="true" />
            </key>
            <one-to-many class="com.yz.pojos.Orders" />
        </set>
    </class>
</hibernate-mapping>

訂單與客戶---多對一
package com.yz.pojos;

import java.util.Date;

/** *//**
* Orders generated by MyEclipse Persistence Tools
*/

public class Orders implements java.io.Serializable {

    // Fields

    private Integer oid;
    //在多個訂單中，每個訂單只能屬于一個客戶，屬于多對一關系，所以要告訴每個訂單屬于哪一個客戶對象
    private Customer customer;

    private Date odate;

    // Constructors

    /** *//** default constructor */
    public Orders() {
    }

    /** *//** full constructor */
    public Orders(Customer customer, Date odate) {
        this.customer = customer;
        this.odate = odate;
    }

    // Property accessors

    public Integer getOid() {
        return this.oid;
    }

    public void setOid(Integer oid) {
        this.oid = oid;
    }

    public Customer getCustomer() {
        return this.customer;
    }

    public void setCustomer(Customer customer) {
        this.customer = customer;
    }

    public Date getOdate() {
        return this.odate;
    }

    public void setOdate(Date odate) {
        this.odate = odate;
    }

}

<?xml version="1.0" encoding="utf-8"?>

<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"

"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<!--

Mapping file autogenerated by MyEclipse Persistence Tools

-->

<hibernate-mapping>

</id>

<many-to-one name="customer" class="com.yz.pojos.Customer" fetch="select">

</many-to-one>

</property>

</class>

</hibernate-mapping>

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