<rt id="bn8ez"></rt>
<label id="bn8ez"></label>

  • <span id="bn8ez"></span>

    <label id="bn8ez"><meter id="bn8ez"></meter></label>

    posts - 97,  comments - 93,  trackbacks - 0
    Problem Statement

    A speed radar is installed in a highway zone where the maximum speed limit is maxLimit mph, and the minimum speed limit is minLimit mph. Any reading that is strictly above or below this interval is an infringement.
    Periodically, the radar readings are analyzed to make sure that the sensors are working properly. It is assumed that most drivers obey speed limits, and therefore, the radar will be considered faulty if more than 10% of its readings are infringements.
    Given the radar readings over a period of time, return the average speed of all cars that are driving within the speed limits. If the radar is faulty, return 0.0.
    Definition
    ????
    Class:
    SpeedRadar
    Method:
    averageSpeed
    Parameters:
    int, int, int[]
    Returns:
    double
    Method signature:
    double averageSpeed(int minLimit, int maxLimit, int[] readings)
    (be sure your method is public)


    Notes
    -
    The returned value must be accurate to within a relative or absolute value of 1E-9.
    Constraints
    -
    maxLimit will be between 1 and 200, inclusive.
    -
    minLimit will be between 1 and maxLimit, inclusive.
    -
    readings will contain between 1 and 50 elements, inclusive.
    -
    Each element of readings will be between 1 and 200, inclusive.
    Examples
    0)

    1
    50
    {45, 40, 50}
    Returns: 45.0
    With all drivers within the speed limits, the return value is just the average speed.
    1)

    1
    50
    {42,43,44,45,46,47,48,49,50,51}
    Returns: 46.0
    There is only one driver infringing the limit, and it represents 10% of the total readings. The average speed of the other readings is 46.0.
    2)

    1
    50
    {42,46,48,50,52}
    Returns: 0.0
    Only one reading is outside the given limits, but it represents 20% of the total number of readings. We therefore assume that the radar is not working and return 0.0.
    3)

    20
    60
    {25,45,45,43,24,9,51,55,60,34,61,23,40,40,47,49,33,23,47,54,54}
    Returns: 41.68421052631579

    This problem statement is the exclusive and proprietary property of TopCoder, Inc. Any unauthorized use or reproduction of this information without the prior written consent of TopCoder, Inc. is strictly prohibited. (c)2003, TopCoder, Inc. All rights reserved.
     1 /**
     2   * Author Nicky Qu
     3   * All Rights Reserved Oct 20th, 2007
     4 */
     5 import java.util.Formatter;
     6 
     7 public class SpeedRadar{
     8   private double averageReading = 0.0;
     9    public double averageSpeed(int minLimit,int maxLimit,int[] readings){
    10       int sum = 0;
    11       int countinF = 0;
    12       double rate =0.0;
    13       for(int i=0;i<readings.length;i++){
    14          if((readings[i]> minLimit-1)&&(readings[i]<maxLimit+1)){
    15          sum = sum +readings[i];
    16          }else{
    17            countinF+=1;
    18            rate = countinF*1.0/readings.length;
    19            if(rate>0.1){
    20               sum = 0;
    21               break;
    22             }
    23          }
    24       }
    25       averageReading = sum*1.0/(readings.length-countinF);
    26       Formatter f = new Formatter();
    27       return Double.parseDouble(f.format("%.15e", averageReading).toString());
    28    }
    29 }


    posted on 2007-10-20 13:25 wqwqwqwqwq 閱讀(1262) 評論(1)  編輯  收藏 所屬分類: Data Structure && Algorithm

    FeedBack:
    # re: TopCoder TCHS1
    2007-10-22 13:29 | 曲強 Nicky
    public class SpeedRadar {

    public double averageSpeed(int minLimit, int maxLimit, int[] readings) {
    int bad = 0;
    int sum = 0;
    for (int a : readings)
    if (a < minLimit || a > maxLimit)
    bad++;
    else
    sum += a;
    if(bad*10>readings.length)
    return 0.0;
    else
    return sum*1./(readings.length-bad);
    }
    }  回復  更多評論
      
    <2007年10月>
    30123456
    78910111213
    14151617181920
    21222324252627
    28293031123
    45678910




    常用鏈接

    留言簿(10)

    隨筆分類(95)

    隨筆檔案(97)

    文章檔案(10)

    相冊

    J2ME技術網站

    java技術相關

    mess

    搜索

    •  

    最新評論

    閱讀排行榜

    校園夢網網絡電話,中國最優秀的網絡電話
    主站蜘蛛池模板: 美女被艹免费视频| 亚洲色偷偷av男人的天堂| 亚洲中文字幕无码亚洲成A人片| 日本免费电影一区二区| 亚洲AV无码精品色午夜在线观看| 中文字幕高清免费不卡视频| 久久噜噜噜久久亚洲va久| 国产成人免费视频| 91精品国产亚洲爽啪在线观看| 91短视频免费在线观看| 亚洲在成人网在线看| 无码一区二区三区免费视频| 亚洲中文字幕久久精品无码A | 成人性做爰aaa片免费看| 亚洲日韩乱码中文无码蜜桃臀网站 | 亚洲成人在线免费观看| 亚洲视频在线观看免费视频| 日本阿v免费费视频完整版| 亚洲午夜无码毛片av久久京东热 | 妞干网在线免费观看| 国产精品亚洲精品久久精品| 亚洲高清无码在线观看| a毛片久久免费观看| 亚洲精品国产福利片| 免费无码又黄又爽又刺激| 老司机午夜性生免费福利| 亚洲精品狼友在线播放| 日本成年免费网站| 色哟哟国产精品免费观看| 亚洲AV无码成人精品区蜜桃| 国产精品入口麻豆免费观看| 国产亚洲精品AAAA片APP | 国产亚洲精品激情都市| 无码国产精品一区二区免费模式 | 99久久国产免费-99久久国产免费| 亚洲免费闲人蜜桃| 亚洲国产精品视频| 69影院毛片免费观看视频在线| AV激情亚洲男人的天堂国语| 亚洲国产精品第一区二区| 国产一区二区三区免费看|