知止而后有定，定而后能靜，靜而后能安，安而后能慮，慮而后能得。物有本末，事有終始。知所先后，則近道矣。
gcd(a,b) = gcd(b, a mod b) 求a,b的最大公約數(shù)d 有 a = bk + r a = x*d b = y*d -> r = a - bk (即a mod b) r = xd - ydk r = (x-yk)d 即d也可以被a mod b整除,d是a mod b的公約數(shù) 因?yàn)閐是b的公約數(shù) 所以 gcd(b,a mod b)成立
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